Club X and Club Y

IMO it is C.

using set theory we get

X/5 = 3/10 Y

hence X = 15/10 Y

as X,Y >0 and belongs to Integer.

let me know OA please.

regards,

Can you walk me through the set theory in a little more detail?

When I run through the problem quickly picking a few numbers and drawing some venn diagrams, I can come up with multiple scenarios where either X is greater, less than or equal to Y that will still satisfy the overlap restrictions of the two statements together.

Thanks!

OA is C...Cubicle bound misfit, can you walk me through the problem in a more simplistic manner? i didnt understand the set theory at all...

It can be simplified by taking
20% ox X = 30%of Y

Hence X > Y

With the two sentences,
There are people who are in X, people who are in Y and people who are in X and Y.
The number of people who are in X and who also are in Y is the same number as the one of Y who are alos in X.
But we see that this proportion of people who are in both is different between X and Y.
It represents much more for Y than for X so Y is smaller than X.

Example:
150 persons in X
90 persons in Y
30 persons represents only 30/150=20% of X but 30 persons represents 30/90=33,3% of Y