

As you can see from the image, the radius would have to be 4. Therefore, the maximum possible area would be 16pi
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RedeemIf the radius is 7, then the leftmost point on the circle will be (-3, 0), which violates the no negatives rule.aditi_bc wrote:I understand that the circle need to be in the first quadrant but fail to understand the logic behind radius=4 (& not 7). Could you pl explain further?
