C is fine

St 1: This only tells that AOB is right triangle. It does not give much information to find perimeter...INSUFF
St 2: Area of the triangle = 24. With st 2 alone we cannot assume AOB is a right triangle. Again there is no way we can find sides AB and AO.....INSUFF

Combining

b^2+h^2 = 100
bh = 48
(b+h)^2 = b^2+h^2+2bh
= 100 + 96
= 196

We can find b+h. Just add 10 to it and youll get the perimeter. So C is fine.

4meonly wrote:OA is C but I got B

Let me try to explain...

let AB=b and BO=h. Therefore, the perimeter is, b+h+10.

From the first statement, we find out that since B is the mid point of AC, triangle ABC is a right-angled triangle. But, we cannot tell what the base and height are, which is required to figure out the perimeter.
all we can tell is b^2 + h^2 = 100
Therefore, insufficient.


From the second statement, we can say that b*h = 48. but, we do not know if b is perpendicular to h or not. Also, we do not know the value of (b+h). So, insufficient.

From both statements together, since we know the value of b*h and we also know b is perpendicular to h, we can find out the value of (b+h) to be equal to 14. So, the perimeter is b+h+10 = 14+10 = 24.

Hence, the answer is C.

Yes, I see. I found two sides through Pythagoren theorem without any evidence that AOB is right triangle.

4meonly wrote:OA is C but I got B

Beautiful question..man.. What is the Source?

C is the answer.

Think this way.. without statement 1 .. for stat2. you can get many triangle for given area ratio (6:25 pi). But perimeter will definitely change..


If question asks what is the area of triangle AOB? Then Answer would be B.