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Circle and Square

Expert replies
by gmattesttaker2 » Fri Feb 21, 2014 11:34 pm
Hello,

Can you please tell me if my answer is correct here:

In the figure above, the circle is inscribed in the square. If the square has side of length 100. then the perimeter of the square is approximately how much greater than the circumference of
the circle?

A) 9,686
B) 2150
C) 243
D) 100
E) 86

I am getting 100

Thanks,
Sri
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Source: — Problem Solving |

by Uva@90 » Sat Feb 22, 2014 12:53 am
gmattesttaker2 wrote:Hello,

Can you please tell me if my answer is correct here:

In the figure above, the circle is inscribed in the square. If the square has side of length 100. then the perimeter of the square is approximately how much greater than the circumference of
the circle?

A) 9,686
B) 2150
C) 243
D) 100
E) 86

I am getting 100

Thanks,
Sri
Sri,
Is ans E ?

This is how I did,
Perimeter of Square is 4*100 =400
Perimeter of square is 2*3.14*r
where r = d/2(d= 100) =50
so Perimeter of square =2*3.14*50 =314

400-314 = 86
Hence ans is E

Regards,
Uva.
Known is a drop Unknown is an Ocean
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by theCodeToGMAT » Sat Feb 22, 2014 4:00 am
Indeed, the answer seems to be {E}

Side of Square = 100
So, radius = 50
Circumference = 2 * pi * 50 = 100 * 3.14 = 314
Perimeter = 100 * 4 = 400
Difference = 400 - 314 = 86
R A H U L
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by gmattesttaker2 » Sat Feb 22, 2014 9:43 am
Uva@90 wrote:
gmattesttaker2 wrote:Hello,

Can you please tell me if my answer is correct here:

In the figure above, the circle is inscribed in the square. If the square has side of length 100. then the perimeter of the square is approximately how much greater than the circumference of
the circle?

A) 9,686
B) 2150
C) 243
D) 100
E) 86

I am getting 100

Thanks,
Sri
Sri,
Is ans E ?

This is how I did,
Perimeter of Square is 4*100 =400
Perimeter of square is 2*3.14*r
where r = d/2(d= 100) =50
so Perimeter of square =2*3.14*50 =314

400-314 = 86
Hence ans is E

Regards,
Uva.
Hello Uva,

Thanks for your reply. You are right. The answer is E. Thanks for the explanation. I rounded 3.14 to 3. I think that's where I was going wrong. Thanks again.

Best Regards,
Sri
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