BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Chords in a circle

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 966
Joined: Sat Jan 02, 2010 8:06 amFollowed by: 21 members
Thanked: 230 times
by shankar.ashwin » Thu Sep 15, 2011 2:45 am
What is the maximum number of chords with length 'R' which can be drawn in a circle with radius 'R', such that no two chords intersect inside the circle.

A) 2
B) 4
C) 6
D) 8
E) None of these
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 amFollowed by: 123 members
Location: India
Thanked: 310 times
GMAT Score:750

by cans » Thu Sep 15, 2011 3:17 am
IMO A
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Thu Sep 15, 2011 3:18 am
shankar.ashwin wrote:What is the maximum number of chords with length 'R' which can be drawn in a circle with radius 'R', such that no two chords intersect inside the circle.

A) 2
B) 4
C) 6
D) 8
E) None of these
Image

The 6 possible chords form the hexagon shown above.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 amFollowed by: 123 members
Location: India
Thanked: 310 times
GMAT Score:750

by cans » Thu Sep 15, 2011 4:34 am
But don't they intersect? (They share a common end point)
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 966
Joined: Sat Jan 02, 2010 8:06 amFollowed by: 21 members
Thanked: 230 times

by shankar.ashwin » Thu Sep 15, 2011 4:38 am
Hi Cans, the OA is 6.
They mention in the question that the chords should not intersect inside the circle. 2 chords meeting at the circumference, they do not actually intersect.

The problem tests us on the concept that 6 eq. triangles with side 'a' constitute a hexagon which can be inscribed inside a circle of radius 'a'.

Tricky sum
cans wrote:But don't they intersect? (They share a common end point)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Thu Sep 15, 2011 6:21 am
cans wrote:But don't they intersect? (They share a common end point)
Yes, but they intersect ON the circle, so they satisfy the condition that no two chords intersect INSIDE the circle.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1239
Joined: Tue Apr 26, 2011 6:25 amFollowed by: 26 members
Thanked: 233 times
GMAT Score:680

by sam2304 » Thu Sep 15, 2011 10:32 am
If that is the case then an octagon inscribed in a circle will have 8 chords and they won't intersect as well. It can be more as well say a 10 sided figure in a circle. Draw 15 parallel lines in a circle, each of them are chords and none of them will intersect each other. So shouldn't it be none of these. As a matter of fact a circle can have infinite number of chords not intersecting each other. Correct me if i am wrong.
Getting defeated is just a temporary notion, giving it up is what makes it permanent.
https://gmatandbeyond.blogspot.in/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1239
Joined: Tue Apr 26, 2011 6:25 amFollowed by: 26 members
Thanked: 233 times
GMAT Score:680

by sam2304 » Thu Sep 15, 2011 10:34 am
Extremely sorry :(. My bad i din't notice the length R equal to radius mentioned in the problem. :)
Getting defeated is just a temporary notion, giving it up is what makes it permanent.
https://gmatandbeyond.blogspot.in/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 979
Joined: Tue Apr 14, 2009 1:38 amFollowed by: 12 members
Location: Hyderabad, India
Thanked: 49 times
GMAT Score:700

by bubbliiiiiiii » Fri Sep 16, 2011 12:40 am
GMATGuruNY wrote:
shankar.ashwin wrote:What is the maximum number of chords with length 'R' which can be drawn in a circle with radius 'R', such that no two chords intersect inside the circle.

A) 2
B) 4
C) 6
D) 8
E) None of these
Image

The 6 possible chords form the hexagon shown above.

The correct answer is C.
Is this an established theorm?

I mean should we make note of this point remember for future problems?
Regards,

Pranay
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1