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There are 5 chess amateurs and each chess amateur plays with exactly 4 other amateurs. So, number of ways of playing a participant games = 5 * 4 = 20pemdas wrote:There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total number of chess games possible to be played in the tournament?
A 10
B 20
C 40
D 60
E 120
made up
