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charge for the first one mile

Expert replies
by sanju09 » Sat Jul 31, 2010 4:30 am
If the cab charge for the first one mile is $1 and every subsequent 1/5th of a mile or fraction thereof is charged at 'a' cents, what is the total charge payable in cents for a distance of 'b' miles where 'b' is a whole number?
A. 1 + (b – 1) 5 a
B. 5 a b
C. 100 + (b – 1) 5 a
D. 100 + a b
E. 100 + (b – 1) a

[spoiler]Source: winningprep.com[/spoiler]
The mind is everything. What you think you become. –Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

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Source: — Problem Solving |

by charan_nannuri » Sat Jul 31, 2010 4:45 am
charge for 1st mile = 1$=100 cents
after 1st mile charge for 1/5 th mile = a cents => charge for every mile after 1st mile =5a cents

charge for b miles = charge for 1st mile +charge for (b-1) miles
=100+(b-1)5a

so ANS :C
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by sanju09 » Sat Jul 31, 2010 4:50 am
charan_nannuri wrote:charge for 1st mile = 1$=100 cents
after 1st mile charge for 1/5 th mile = a cents => charge for every mile after 1st mile =5a cents

charge for b miles = charge for 1st mile +charge for (b-1) miles
=100+(b-1)5a

so ANS :C
excellent charan_nannuri! your most welcome!! please keep pouring in more for us

I can see you joined on 11 Nov 2009, and this is your first post on 31 Jul 2010, how come?
The mind is everything. What you think you become. –Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
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by dinesh19aug » Sat Jul 31, 2010 1:56 pm
Sanju,
I see that solution is already posted. However whenever you come across such questions where answer involves ONLY VARIABLES, then you can plug in random values.

So lets us say that a = 1 cents(1 mile 5a = 5 cents), and b = 2 miles
Now find the charge: 100 + (2-1)* 5 = 105

Check the values in the options and only C satisfies it.


Thanks,
Dinesh
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