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2^0, y^0 and z^0 are all giving the same value 1.junegmat221 wrote:@Rahul,
this method takes odd factors namely
2 to the power 0 ,
y to the power 0 (since y is odd and 2 is the only even prime)
y to the power 1
z to the power 0 (since z is odd and 2 is the only even prime)
z to the power 1
I thought these five would negate the Total number of factors(16) and result in 11...
Am i doing anything wrong here..????
I had doubts on this and Rather plugged in the smalles values in y and z namely 3 and 5 and computed the even divisors of
8 * 3 * 5 which are 2,4,6,8,10,12,20,30,40,50,60 which comes to eleven..But this method really kills my time..
