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Cats and dogs

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by immaculatesahai » Wed Dec 14, 2011 2:27 am
B is correct.

60= only Cats+ only Dogs+ cats and dogs+ neither cats or dogs

We are given from St2 that cats and dogs= neither cats or dogs

Therefore 60= (only cats+cats and dogs) + (only dogs+ cats and dogs)

Hence 60=38 + Families that own dogs (this includes famiies that have only dogs and also own dogs and cats)

Hence ans is 22.

B wins.
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by ArunangsuSahu » Tue Dec 27, 2011 8:40 pm
In the problem statement the following things are not known

1) How many of the families neither have a cat nor have a dog?

OR

2) How many families only have dog?

S-Neither = D + C -D and C

Statement 1:

Only Cat =28
Cat or Cat and Dog(D and C) = 38

So the above equation doesn't satisfy. Therefore Statement 1 is INSUFFICIENT

Statement 2:
S-X= D+C-X
60 = D+38
D = 22

Therefore, Statement 2 is SUFFICIENT

So B is the answer
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by ronnie1985 » Fri Mar 30, 2012 9:57 am
Using venn diagram, it can easily seen that (C) is the answer
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by Ganesh hatwar » Mon Aug 06, 2012 1:33 am
DanaJ wrote:Source: Veritas Prep

Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?

(1) 28 of the families in this neighborhood have a cat but not a dog
(2) The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.

Experts: only Veritas Prep experts, please!
T-n = A+B - both

68- n= 38+B- both

From 2 we know n = both so

68 = 38 + B

so B = 30

Ans B
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by Ganesh hatwar » Mon Aug 06, 2012 1:34 am
Ganesh hatwar wrote:
DanaJ wrote:Source: Veritas Prep

Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?

(1) 28 of the families in this neighborhood have a cat but not a dog
(2) The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.

Experts: only Veritas Prep experts, please!
T-n = A+B - both

68- n= 38+B- both

From 2 we know n = both so

68 = 38 + B

so B = 30

Ans B
Its not 68 but 60
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by ritzzzr » Sun Feb 17, 2013 11:07 pm
Image
From Statement 1:
We get
a+c = 38
so c = 10
but we cannot tell the number of families having dog since we dont know the number of families not having cat & dog
From statement 2:
we know
c=n
a+b+c+n=60
a+b+c+c=60
a+c=38
so b+c =22
So number of family having dogs is 22
So statement 2 is enough
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by David@VeritasPrep » Mon Feb 18, 2013 6:40 am
Glad to see that this one is still getting responses!!

Nice diagram ritzzzr!

This one is B, which is not totally expected right? Lots of people go for C. But this is a B - A - D subject. I actually wrote about this exact problem as part of a much larger article called "Data Sufficiency Jujitsu: Part 1.

https://www.beatthegmat.com/mba/2013/01/ ... d-subjects
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by rajeshsinghgmat » Thu Feb 21, 2013 5:12 pm
C in answer.
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by Salma178 » Thu Apr 11, 2013 12:16 am
Source: Veritas Prep

Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?

1. 28 of the families in this neighborhood have a cat but not a dog
2. The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.

Hi Here's my solutions to the problem:

Solution A Cats No Cats Total

Dogs 10 ?

No Dogs 28

Total 38 22 60

In-sufficient because "?" can't be determined.

Solution B Cats No Cats Total

Dogs x 22-x 22

No Dogs 38-x x 38

Total 38 22 60

In the above Cat & Dog = X and No Cat & No Dog = X

Sufficient because Dogs = 22.

Therefore the answer is B.
Attachments
Workings.xlsx
Apologies my tables are not clear in the answer posted. Please refer the attachment for the same.
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by aceacharya » Sun Apr 14, 2013 5:25 pm
This is pretty easy

Has to be B
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by David@VeritasPrep » Sun Apr 14, 2013 6:08 pm
Pretty Easy?

It is better if you do not use that four-letter-word. As soon as you think something is easy, you miss it.

Here is an article about easy questions https://www.beatthegmat.com/mba/2012/12/ ... n-the-gmat
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by [email protected] » Sat Nov 30, 2013 2:11 am
Nicely explained David Thanks!

David@VeritasPrep wrote:OA is B.

The explanations above are correct. For those who need a little slower paced explanation as to why B works, the following gives some more detail.

Correct answer: (B)

Solution: On any Venn diagram problem it is helpful to draw out the two sets and also note the formula Total = Set 1 + Set 2 - Both + Neither. The question stem tells us that the total number of families is 60 and the total number of families with a cat is 38. The question is asking whether we can determine the total number of families who have a dog.

Statement (1) tells us that 28 families have a cat but not a dog. If there are 38 families in total that have a cat, this information tells you that 10 families (38-28) must have both a dog and a cat. It does not, however, give you any information about the number of families who have only a dog or neither a dog nor a cat. It is therefore impossible to determine how many total families have a dog. Note that because the question stem does not say that all the familes own a cat, a dog, or both, some households could own neither.

Statement (2) tells us that the number of families who have both a cat and a dog is the same as the number who have neither. This information does not appear to be sufficient at first glance but a closer look at the Venn diagram formula for two set problems shows that it is. Remember our formula from above: Total Familes = # of Families with a Cat (C) + #of Families with a Dog (D) - Families with Both (B) + Families with Neither (N). Or, with variables, T = C + D - B + N. Plug in the information from the question stem and Statement (2) to find that T = 60, C = 38, and B=N. We can then solve for D using the formula. 60 = 38 + D - B +B. D = 22. Statement (2) alone is sufficient.

So it was actually helpful that the information from the question stem gave the total families with cats and the question was asking about the total number of families with dogs. Because we are working with totals, the Both and the Neither Categories cancel out given the information in statement 2 that these two categories are equal.

Nice work guys!
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by Veera123 » Wed Jan 15, 2014 1:39 am
Thanks all for the good explanations.
What difficulty level would you rate this question?
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by Matt@VeritasPrep » Wed Jan 15, 2014 12:00 pm
Veera123 wrote:Thanks all for the good explanations.
What difficulty level would you rate this question?
Probably 60th - 70th percentile, but it's from our books (not our online question sets) so I don't think we've determined an exact difficulty for it.

That said, if you try our question bank at gmat.veritasprep.com, you can see the difficulties of each question, as determined by the number of people who've gotten them right so far (and which other questions those people answered correctly, in much the same way that the actual exam determines the difficulty of each question).
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by jaspreetsra » Wed Nov 05, 2014 12:41 am
Ans: B
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