BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Cards - Probability

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 amFollowed by: 1 member
Thanked: 32 times
by Vemuri » Thu Mar 05, 2009 6:02 am
Two cards are drawn from a well-shuffled pack of cards. Given that both the cards are numbered cards, what is the probability that the cards have

(i) Same color on them?
A) 17/35
B) 17/70
C) 34/35
D) 1/35
E) 18/35

(ii) same number & different colors on them?
A) 1/70
B) 1/35
C) 1/26
D) 3/35
E) 2/35
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 69
Joined: Wed Mar 04, 2009 4:15 pm
Thanked: 17 times
GMAT Score:780

by Feep » Thu Mar 05, 2009 1:15 pm
We know that a standard deck of cards has 52 cards in it, but we must remove all non-numbered cards (J, Q, K, A) for the purposes of this problem. There are four suits of each of those cards, so a total of sixteen we must remove, leaving a deck of 36 cards.

In the first problem, we draw the first card, which of course can be any card, leaving 35 cards. Of those 35, only 17 remain that are the same color as the first one you drew. So, 17/35 is the correct answer.

For the second, you draw the first card, which can be any card. Of those remaining, only three are the same number (the other three suits), and two of those three are of a different color than the one you drew. So, the answer is 2/35.
I tutor GMAT/GRE level mathematics privately in the Los Angeles region, as well as via Skype for a discounted rate. Send me a message if you're interested.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 amFollowed by: 1 member
Thanked: 32 times

by Vemuri » Thu Mar 05, 2009 7:41 pm
You are cool !!! Both the answers are right.

Is there any other approach method?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Thu Mar 05, 2009 8:40 pm
Another approach:

Same color:

P(BB) + P(RR)

= 18/36*17/35+18/36*17/35

= 1/2(2 * 17/35)

= 17/35
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 amFollowed by: 1 member
Thanked: 32 times

by Vemuri » Sat Mar 07, 2009 3:16 am
cramya wrote:Another approach:

Same color:

P(BB) + P(RR)

= 18/36*17/35+18/36*17/35

= 1/2(2 * 17/35)

= 17/35
Thank you. This is a simple & clear approach.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 14
Joined: Wed Feb 18, 2009 4:56 pm
Thanked: 1 times

by devesh99 » Mon Mar 09, 2009 6:12 pm
Hi

Cramya .. can you answer the second part of the question??

Feep .. What did u take in the denominator. I understood the logic for numerator i.e. 9*2 but Denominator should be 36*35 rite??

Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 14
Joined: Wed Feb 18, 2009 4:56 pm
Thanked: 1 times

by devesh99 » Mon Mar 09, 2009 6:13 pm
Hi

Cramya .. can you answer the second part of the question??

Feep .. What did u take in the denominator. I understood the logic for numerator i.e. 9*2 but Denominator should be 36*35 rite??

Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1