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Start the planA) 320
B) 480
C) 520
D) 730
E) 920
OA: C
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Start the planAverage of Car X = 25.0 miles/gallonboomgoesthegmat wrote:Car X averages 25.0 miles per gallon of gasoline and Car Y averages 11.9 miles per gallon. If each car is driven 12,000 miles, approximately how many more gallons of gasoline will Car Y use than Car X?
A) 320
B) 480
C) 520
D) 730
E) 920
OA: C
I'm trying to learn every way possible to solve questions so I have tons of ammo when I take the test.[email protected] wrote:Hi boomgoesthegmat,
You've been posting large blocks of questions, but you haven't discussed any of YOUR attempt at solving them. Why did you get them wrong? What did you miss? What aspect of each question are you really interested in. It's a good bed that all of these questions have been discussed somewhere online already, so what specifically are you looking for when YOU post them?
boomgoesthegmat wrote:Car X averages 25.0 miles per gallon of gasoline and Car Y averages 11.9 miles per gallon. If each car is driven 12,000 miles, approximately how many more gallons of gasoline will Car Y use than Car X?
A) 320
B) 480
C) 520
D) 730
E) 920 /quote]
To solve this problem we will need to use the formula: rate x gallons = distance, which means:
gallons = distance/rate
We need to calculate the number of gallons used by car X and the number of gallons used by car Y. Let’s start with car X.
For car X, we know the following:
rate = 25
distance = 12,000
gallons = 12,000/25 = 480 gallons
For car Y, we know the following:
rate = 11.9
Since we are told we can approximate, we can round up the rate of Car Y to 12.
distance = 12,000
gallons = 12,000/12 = 1,000
Thus, we can say that car Y will use approximately 1,000 – 480 = 520 more gallons of gasoline than car X.
Answer: C
