Answer with reasoning
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I think that's what makes the difference in the real exam. A tough question will be tedious to answer (not necessarily always) & someone who is very good (caliber of above 720) will quickly do a comfortable approximation & arrive at the answer, while someone like me would sit calculating each component, spend a lot of energy & get bogged down by the ticking time :roll:cm47323 wrote:Unless I missed some way to simplify the math, this problem isn't very GMATy. First need to take sqrt(1256/pi) to get the radius. You can guesstimate to around 20. Then need the circumference which involves multiplying by pi and then dividing the distance by the rate. I get 75 as well, but again, I don't see how to avoid doing calculations using a numerical estimation of pi
I am positive it was a typo anshuleth.anshulseth wrote:One can use relative speed to cut down further on calculations here.
R= sqrt(A/pi) = sqrt(1256/3.14) =sqrt(400) = 20
Time taken(in min.) = (Total Distance / Total relative speed ) *60
= ((2*3.14*20)/100)* 60 = 75 (approx)
Relative speed will be the sum of A & B as they are moving in the same dir.
Cheers