Cant get this concept

[email protected] wrote:The sum of digits of integer z is 186 and z -10^n-4 what is the value of positive integer n

This question doesn't make any sense. Namely, the part in green.
Also, please make the exponents clear.
For example, 10^n-4 can be interpreted as EITHER (10^n)-4 OR 10^(n-4)

Cheers,
Brent

Please go back and edit the original post so that others see the correct question.

Cheers,
Brent

[email protected] wrote:The sum of the digits of integer z is 186 and z=(10^n)-4, what is the value of positive integer n

Since 10^n is a 1 followed by n zeros, we know that z = 999....996
So, how many 9's are there?

The sum of the digits of integer z is 186
So, 9+9+9+9+9+....+9+9+6 = 186
This means that 9+9+9+9+9+....+9+9 = 180
So, there must be 20 9's in the above sum.
So, z = 9999999....9996 (where there are twenty 9's and one 6)
In other words, z is a 21-digit number.
This means that 10^n must be a 22-digit number.
In other words, 10^n must be 1 followed by 21 zeros.
So, n = 21

Cheers,
Brent