candy

kishore: Senior | Next Rank: 100 Posts; Posts: 62; Joined: Fri Dec 21, 2007 2:58 pm; Location: Fremont , California; Thanked: 3 times

How many ways can 3 pieces of candy given out to 4 kids ?

by kishore » Sun Dec 28, 2008 7:36 pm

How many ways can 3 pieces of candy given out to 4 kids ?

4C3 = 4!/1! * 3! = 4 ways

Alternative Explanation:

A, B, C, D are the Kids and 3 candies can be distributed among them as

ABC

ABD

ACD

BCD

Therefore it is 4 ways.

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nh8404052006: Senior | Next Rank: 100 Posts; Posts: 48; Joined: Wed Aug 27, 2008 9:58 am

by nh8404052006 » Sun Dec 28, 2008 7:41 pm

should we consider also the following scenario: if all the candies are given to A and none to others.?

OA: [spoiler]4^3[/spoiler]

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Sachindh: Senior | Next Rank: 100 Posts; Posts: 37; Joined: Wed Sep 17, 2008 8:17 pm; Location: India; Thanked: 4 times

Re: candy

by Sachindh » Sun Dec 28, 2008 7:47 pm

nh8404052006 wrote:How many ways can 3 pieces of candy given out to 4 kids ?

Since it is not given how many candies can be given to any one. it can be assumed that the any particular kid can be given 0-3 candies. Therefor answer would be 4^3.

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vittalgmat: Legendary Member; Posts: 621; Joined: Wed Apr 09, 2008 7:13 pm; Thanked: 33 times; Followed by:4 members

by vittalgmat » Mon Dec 29, 2008 12:35 am

I wonder if this approach is correct.
I found this formula on BTG:

"distributing n identical things among r persons such that any person might get any number ( incl 0) is n+r -1 C r-1"

If I apply this I get 20.

Pls comment.

thanks

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