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by [email protected] » Tue Dec 06, 2011 9:30 pm
Uncle Bruce is baking chocolate chip cookies. He has 36 ounces of dough (with no chocolate) and 15 ounces of chocolate. How many ounces of chocolate are left over if he uses all the dough but only wants the cookies to consist of 20% chocolate?

(A) 3
(B) 6
(C) 7.2
(D) 7.8
(E) 9
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by Anurag@Gurome » Tue Dec 06, 2011 9:41 pm
[email protected] wrote:Uncle Bruce is baking chocolate chip cookies. He has 36 ounces of dough (with no chocolate) and 15 ounces of chocolate. How many ounces of chocolate are left over if he uses all the dough but only wants the cookies to consist of 20% chocolate?

(A) 3
(B) 6
(C) 7.2
(D) 7.8
(E) 9
The question asks how much chocolate is left over.
Let the total weight be T ounces.
Then 80% of T = 36
T = 36/0.80 = 45 ounces
Weight of chocolate used = 45 - 36 = 9 ounces
So, weight of chocolate left over = 15 - 9 = 6 ounces

The correct answer is B.
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by LalaB » Wed Dec 07, 2011 2:30 am
x/(36+x)=1/5
x=9

15-9=6

ans is [spoiler]B[/spoiler]
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by Brent@GMATPrepNow » Mon Sep 09, 2019 2:06 pm
[email protected] wrote:Uncle Bruce is baking chocolate chip cookies. He has 36 ounces of dough (with no chocolate) and 15 ounces of chocolate. How many ounces of chocolate are left over if he uses all the dough but only wants the cookies to consist of 20% chocolate?

(A) 3
(B) 6
(C) 7.2
(D) 7.8
(E) 9
We can also use equivalent ratios

The cookies will consist of 20% chocolate.
In other words, the cookies will consist of 1/5 chocolate.
We can also say the cookies will consist of 4/5 dough.

This means the cookies are 4 parts dough and 1 part chocolate.
So, the dough to chocolate ratio = 4/1

We have 36 ounces of dough available.
Let c = the number of ounces of chocolate needed.

We now can use equivalent ratios to set up the equation: 4/1 = 36/c
Solve to get c = 9

So, we need to USE 9 ounces of chocolate, which leave us with 6 ounces REMAINING.
Answer: B

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by Scott@TargetTestPrep » Thu Sep 12, 2019 10:18 am
[email protected] wrote:Uncle Bruce is baking chocolate chip cookies. He has 36 ounces of dough (with no chocolate) and 15 ounces of chocolate. How many ounces of chocolate are left over if he uses all the dough but only wants the cookies to consist of 20% chocolate?

(A) 3
(B) 6
(C) 7.2
(D) 7.8
(E) 9

Let x = the amount of chocolate to be used so that the cookies consist of 20% chocolate. We have:

x/(36 + x) = 20/100

x/(36 + x) = 1/5

5x = 36 + x

4x = 36

x = 9

Thus, if the cookies are to contain 20% chocolate, 15 - 9 = 6 ounces of chocolate will remain.

Answer: B

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