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Can anyone do this?

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Master | Next Rank: 500 Posts
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by givemeanid » Mon Sep 03, 2007 9:37 am
10X/100 - 8Y/100 = 56
5X - 4Y = 2800

X+Y = 2000 => X = 2000 - Y
5(2000 - Y) - 4Y = 2800
Y = 800
So It Goes
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Source: — Problem Solving |
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Re: Can anyone do this?

by jaspreet.sharma » Mon Sep 03, 2007 11:20 pm
aditya33 wrote:If X dollar is invested @ 10 percent for one year nad Y dollars is invested at 8 percent for one year,the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56.If the dollar 2000 is the total amount invested,how much is invested at 8 percent?

1-280
2:- 800
3:-892
4:-1108
5:-1200 (all figures are in dollars).

I did it in a complex way.Can anyone pls do it in a simple method.
Thnaks.
ATQ
(10*x)/100 – [(2000-x)*8]/ 100 = 56

Solving this eqn

We will Get x= 1200

So ans = 2000-1200 = $ 800
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