Calender

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j_shreyans: Legendary Member; Posts: 510; Joined: Thu Aug 07, 2014 2:24 amFollowed by: 5 members; Thanked: 3 times

by j_shreyans » Sun Apr 26, 2015 4:43 am

If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140

If I let c = the number of calendars she usually buys, and p = the dollar value of the standard price of one calendar, I can say that (1.5c) (0.8p) is her total cost at the discounted price.I get (1.5c) (0.8p) = 1.2cp. 120 times the standard price of one calendar is 120p.

Now what should I do after this.

Please help and advise.

Thanks ,

Shreyans

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Source: Beat The GMAT — Problem Solving | Sun Apr 26, 2015 4:43 am

GMATGuruNY: GMAT Instructor; Posts: 15539; Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members; Location: New York, NY; Thanked: 13060 times; GMAT Score:790

by GMATGuruNY » Sun Apr 26, 2015 6:08 am

j_shreyans wrote:If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140

Let the standard price = $10.

She will be given a 20% discount off the standard price.
Discounted price = 10 - 20% of 10 = $8.

Her total cost would then be 120 times the dollar value of the standard price of one calendar.
Total cost = 120*10 = $1200.

For a total cost of $1200, the number of calendars that can be purchased at the discounted price of $8 = 1200/8 = 150.

A stationery store owner buys 50% more identically-priced calendars than she usually purchases.
Since the 150 calendars purchased at the discounted price represent 50% more than the number usually purchased, the number usually purchased = 100.

The correct answer is C.

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theCEO: Master | Next Rank: 500 Posts; Posts: 363; Joined: Sun Oct 17, 2010 3:24 pmFollowed by: 3 members; Thanked: 115 times

by theCEO » Sun Apr 26, 2015 6:38 am

j_shreyans wrote:If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140

If I let c = the number of calendars she usually buys, and p = the dollar value of the standard price of one calendar, I can say that (1.5c) (0.8p) is her total cost at the discounted price.I get (1.5c) (0.8p) = 1.2cp. 120 times the standard price of one calendar is 120p.

Now what should I do after this.

Please help and advise.

Thanks ,

Shreyans

Continuing from where you left off..

There are 2 equations for the total cost:
1. The one you calculated : 1.2cp
2. The one given in the question: 120p

setting these 2 equations to equal each other we get
1.2cp = 120p
1.2c = 120
c = 120 / 1.2
c= 100

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Jeff@TargetTestPrep: GMAT Instructor; Posts: 1462; Joined: Thu Apr 09, 2015 9:34 amFollowed by: 22 members; Location: New York, NY; Thanked: 39 times

by Jeff@TargetTestPrep » Wed Dec 13, 2017 7:06 am

j_shreyans wrote:If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?

A)40
B)80
C)100
D)120
E)140

We can let q = the normal quantity purchased and p = the regular price. Thus:

(1.5q)(0.8p) = 120p

(1.5q)(0.8) = 120

1.2q = 120

q = 120/1.2 = 100

Answer: C

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Head of GMAT Instruction
[email protected]

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