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Box W and V

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by gmat740 » Sat Aug 01, 2009 7:52 pm
Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 19 inches less that the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?
(A) 3
(B) 6
(C) 12
(D) 18
(E) 24


OA-E

I came up with answer=25. Just need to confirm.

My solving

R+19 =W
R-6 = V

So, W- V =25.
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by truplayer256 » Sun Aug 02, 2009 6:48 am
Average length of sticks in Box W=x

Length of each red stick=x-19

Average length of sticks in Box V= x-19-6=x-25

x-(x-25)=25
Last edited by truplayer256 on Sun Aug 02, 2009 10:59 am, edited 1 time in total.
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by shahdevine » Sun Aug 02, 2009 9:09 am
you're right looks like typo.
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by truplayer256 » Sun Aug 02, 2009 10:59 am
Yeah, I made a slight typo at the end there. I'll fix it though B-)
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by gmat740 » Tue Aug 04, 2009 6:56 am
so you guys say, the answer has to be 25 and not 24??

Even I feel the same.
Thanks a lot for discussion
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