Both car A and car B set out from their original locations at exactly the same time and on exactly the same route. Car A drives from Morse to Houston at an average speed of 65 miles per hour. Car B drives from Houston to Morse at 50 miles per hour, and then immediately returns to Houston at the same speed and on the same route. If car B arrives in Houston 2 hours after car A, how many hours did it take car A to make its trip?
A. 0.50
B. 1.00
C. 1.25
D. 1.33
E. 2.00
The OA is C.
I get the solution in the following way,
Car A: 65m/h
Car B: 50m/h
Houston to morse = m = distance
speed=disttimespeed=disttime
Car A:
65m/h=mt
m=65*t ....equation 1
Car B:
50m/h=2m(t+2)
2m=50*t+50∗2
m=25*t+50....equation 2
Combining equation 1 and 2
65*t=25*t+50
40*t=50
t=5/4
t=1,25.
Please, can anyone explain another way to get the solution? Thanks!
A. 0.50
B. 1.00
C. 1.25
D. 1.33
E. 2.00
The OA is C.
I get the solution in the following way,
Car A: 65m/h
Car B: 50m/h
Houston to morse = m = distance
speed=disttimespeed=disttime
Car A:
65m/h=mt
m=65*t ....equation 1
Car B:
50m/h=2m(t+2)
2m=50*t+50∗2
m=25*t+50....equation 2
Combining equation 1 and 2
65*t=25*t+50
40*t=50
t=5/4
t=1,25.
Please, can anyone explain another way to get the solution? Thanks!
