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by blaster » Mon Dec 13, 2010 10:54 am
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?
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by Night reader » Mon Dec 13, 2010 1:01 pm
blaster wrote:If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?
ok now - call vinegar concentration x% => x/100

12x%/(12+50) = 3/100 => 12x/100*(12+50) = 3/100 => {whole percents} 12x/(12+50) = 3 => 12x=3*(12+50) => x=186/12 or 15.5%
answer: 15.5% vinegar 84.5% water
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