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gmatmachoman: Legendary Member; Posts: 2326; Joined: Mon Jul 28, 2008 3:54 amFollowed by: 2 members; Thanked: 173 times; GMAT Score:710

by gmatmachoman » Fri Mar 12, 2010 9:49 am

For a recent play performance, the ticket prices were $25 per adult and $15 per child. A
total of 500 tickets were sold for the performance. How many of the tickets sold were for
adults?
(1) Revenue from ticket sales for this performance totaled $10,500.
(2) The average (arithmetic mean) price per ticket sold was $21.

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Source: Beat The GMAT — Data Sufficiency | Fri Mar 12, 2010 9:49 am

hooliganpete: Junior | Next Rank: 30 Posts; Posts: 20; Joined: Wed Jan 13, 2010 1:28 pm

by hooliganpete » Fri Mar 12, 2010 10:05 am

Here's my stab at it:

From the question stem we know that there are 500 tickets sold, A of which are adult tickets and C of which are child tickets. Thus, A+C=500.

1) From this we can set up the equation: revenue earned = (# adult tickets sold x price) + (# child tickets sold x price2)

or
10,500=25A+15C --> here there are 2 variables and two distinct equations. SUFFICIENT

2) Here we are given the average, thus: 21=(25A+15C)/500
Again we now have two variables and two equations, the one we derived is the same as the equations from 1). SUFFICIENT

IMO D

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mohit11: Master | Next Rank: 500 Posts; Posts: 293; Joined: Thu Jan 14, 2010 9:08 amFollowed by: 5 members; Location: India; Thanked: 36 times; GMAT Score:730

by mohit11 » Fri Mar 12, 2010 10:30 am

hooliganpete wrote:Here's my stab at it:

From the question stem we know that there are 500 tickets sold, A of which are adult tickets and C of which are child tickets. Thus, A+C=500.

1) From this we can set up the equation: revenue earned = (# adult tickets sold x price) + (# child tickets sold x price2)

or
10,500=25A+15C --> here there are 2 variables and two distinct equations. SUFFICIENT

2) Here we are given the average, thus: 21=(25A+15C)/500
Again we now have two variables and two equations, the one we derived is the same as the equations from 1). SUFFICIENT

IMO D

D is the answer. My reasoning is same as above.

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