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by madhan_dc » Thu Feb 10, 2011 8:10 pm
Does the avg (arith. mean) of a, b, c equal c?

1. c-a = c+b

2. c=0

my answer is 1.

book answer is 3 1 and 2 are sufficent.


my approach

from 1, a+b = 0

mean a+b+c/3 = 0+c/3

since c/3 cannot be equal to c i thought 1 is sufficent.
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Source: — Data Sufficiency |

by anshumishra » Thu Feb 10, 2011 8:40 pm
madhan_dc wrote:Does the avg (arith. mean) of a, b, c equal c?

1. c-a = c+b

2. c=0

my answer is 1.

book answer is 3 1 and 2 are sufficent.


my approach

from 1, a+b = 0

mean a+b+c/3 = 0+c/3

since c/3 cannot be equal to c i thought 1 is sufficent.
Is c = (a+b+c)/3 ?

Statement 1:
c-a = c+b
=> a+b = 0, so (a+b+c)/3 = c/3

Is c/3 = c , yes, if c is 0; no, if c ≠ 0
Hence, Insufficient

Statement 2:
c=0 Insufficient

Combining 1 and 2 :
(a+b+c)/3 = c/3 = c , since c=0 --- Sufficient

So, the answer is C
Thanks
Anshu

(Every mistake is a lesson learned )
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