Answer should be A

if you take 2,4,6,8,10
average is 6
eliminate D and E

if you take -4,-2,0,2,4
average 0
eliminate B and C
A is left

Hence A is the answer.

parallel_chase wrote:Answer should be A

if you take 2,4,6,8,10
average is 6
eliminate D and E

if you take -4,-2,0,2,4
average 0
eliminate B and C
A is left

Hence A is the answer.

Thanks I was thinking in wrong way.....

parallel_chase wrote:Answer should be A

if you take 2,4,6,8,10
average is 6
eliminate D and E

if you take -4,-2,0,2,4
average 0
eliminate B and C
A is left

Hence A is the answer.

I agree with your number picking, but your answer choice elimination has me confused!

From {2, 4, 6, 8, 10}, we have x = 6.

So, we can eliminate any choice that contains:

III x is a multkiple of 5

eliminate: (b), (d) and (e).

The two remaining choices are I only and I and II only. So, we automatically know that I must be true. Now we want to pick numbers to show that II need not be true:

{-4, -2, 0, 2, 4} gives us x = 0.

Now we can eliminate any choice containing:

II x is a non-zero integer.

Eliminate (c), choose (a).