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average problem

Problem Solving — algebra and arithmetic
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by R.K » Sat Jun 02, 2012 6:43 pm
At an examination there were 7 candidates of the age f 15; 33 of 16:9 of 14 and 12 of 13; find their average age?
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by Birottam Dutta » Sat Jun 02, 2012 7:05 pm
The answer will be

(7*15 +33*16 +9*14 +12*13)/(7+33+9+12).

You can calculate and find the answer this way.
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by hey_thr67 » Sat Jun 02, 2012 11:01 pm
As the calculation can be quite long. Looking at the numbers you can approximately say that average should be between 15-16.
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by Jim@StratusPrep » Mon Jun 04, 2012 11:07 am
The best way is to subtract 13 from all of the numbers at the beginning and add it back at the end:

(7*2 + 33*3 + 9*1 + 12*0) / (7+33+9+12)

14+99+9/40+21

123/61 is about 2

2+13 = 15, so the answer is just above 15

Makes the math easier.
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by dhonu121 » Thu Jun 07, 2012 8:02 pm
This is a simple weighted average problem
I really like Jim's method.
If you've liked my post, let me know by pressing the thanks button.
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