BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Average height

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Junior | Next Rank: 30 Posts
Posts: 14
Joined: Fri Mar 09, 2007 5:10 pm
Location: San Francisco
by snapplesf » Mon Mar 12, 2007 9:12 am
Hello,

This is my first post. So please correct me if I'm not following an expected procedure -

DS Question - Source: - Practise Test from mba.com
------------------------------------------------------------

What is the average height of the n people in a certain group ?

1) The avg. height of the n/3 tallest people in the group is 6ft and the avg. height of rest of the people is 5ft.

2)The sum of heights of the n people is 178.





Answer is A.

I picked C. I don't understand how you can arrive at a figure using just A. Using A&B , I could set up an equation to solve for n.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member
Location: India
Thanked: 51 times

Re: Average height

by gabriel » Mon Mar 12, 2007 1:21 pm
snapplesf wrote:Hello,

This is my first post. So please correct me if I'm not following an expected procedure -

DS Question - Source: - Practise Test from mba.com
------------------------------------------------------------

What is the average height of the n people in a certain group ?

1) The avg. height of the n/3 tallest people in the group is 6ft and the avg. height of rest of the people is 5ft.

2)The sum of heights of the n people is 178.





Answer is A.

I picked C. I don't understand how you can arrive at a figure using just A. Using A&B , I could set up an equation to solve for n.

The q shuld be posted in the DS section....

nywayz.... the q is based on weighted average .... read this for more information on weighted average https://en.wikipedia.org/wiki/Weighted_mean ..... since the ratio of the people who are 6 ft and the pople who are 5 ft is known we can find the average ht of the entire group.... so the answer in this case wuld be 6*1/3+5*2/3.... so the answer is a...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 14
Joined: Fri Mar 09, 2007 5:10 pm
Location: San Francisco

thanks !

by snapplesf » Mon Mar 12, 2007 2:20 pm
Thanks gabriel !
Had no idea that weighted averages were tested on the gmat.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Tue Dec 21, 2010 10:07 pm

by shobhits » Sat Dec 25, 2010 9:40 pm
The formula to be used is Average height = Sum of heights of all people / number of people.

Statement 1:

Avg. height of the n/3 tallest people = S1 / (n/3) = 6, where S1 is the sum of the heights of the n/3 tallest people.
That gives us S1 = 2n.

Avg. height of the rest of the 2n/3 people = S2 / (2n/3) = 5, where S2 is the sum of the heights of the remaining 2n/3 people.
That gives us S2 = 10n/3.

Average is S1 + S2 / n = [2n + (10n/3)] / n. 'n' will cancel out and you can find the average.


Statement 2:
INSUFFICIENT. Doesn't give the value of n.

And yes, weighted averages are tested on the GMAT.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 165
Joined: Wed Mar 24, 2010 8:02 amFollowed by: 1 member
Thanked: 2 times

by HPengineer » Sat Dec 25, 2010 9:59 pm
I noticed weighted average but made a poor algebra mistake..

((n/3)x6 + (n- n/3)5)/n = Avg


I failed to notice that the Ns will cancel out... moved to quickly and assumed two unknowns = insuffcient
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1