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average distance

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by Gurpinder » Mon Aug 16, 2010 6:53 pm
The average distance between the Sun and a certain
planet is approximately 2.3 × 10^14 inches. Which of the
following is closest to the average distance between
the Sun and the planet, in kilometers? (1 kilometer is
approximately 3.9 × 10^4 inches.)

(A) 7.1 × 10^8
(B) 5.9 × 10^9
(C) 1.6 × 10^10
(D) 1.6 × 10^11
(E) 5.9 × 10^11
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
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Source: — Problem Solving |

by saurabhmahajan » Mon Aug 16, 2010 11:31 pm
2.3 X 10^14 inches/3.9 X 10^4 inches = .589 X10 ^10
which can be equvivalent to 5.9 X 10 ^9

So answer is B.


OA ?
Thanks and regards,
Saurabh Mahajan

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by uwhusky » Mon Aug 16, 2010 11:36 pm
I would round up 3.9 to 4, make 2.3 x 10^14 to 23 x 10^13 and then divide.

23 / 4 = ~5.75, 10^13/10^4 = 10^9.

~5.75 x 10^ 9 = B.
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by kvcpk » Tue Aug 17, 2010 2:24 am
Gurpinder wrote:The average distance between the Sun and a certain
planet is approximately 2.3 × 10^14 inches. Which of the
following is closest to the average distance between
the Sun and the planet, in kilometers? (1 kilometer is
approximately 3.9 × 10^4 inches.)

(A) 7.1 × 10^8
(B) 5.9 × 10^9
(C) 1.6 × 10^10
(D) 1.6 × 10^11
(E) 5.9 × 10^11
No calculation is needed.

(2.3/3.9) * 10^14/10^4
approx 1/2 * 10^10
= approx 5 * 10^9
pick B
"Once you start working on something,
don't be afraid of failure and don't abandon it.
People who work sincerely are the happiest."
Chanakya quotes (Indian politician, strategist and writer, 350 BC-275BC)
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by Gurpinder » Tue Aug 17, 2010 5:27 am
thanks guys

i actually started calculating the numbers..... hahah silly me
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Join the discussion