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Arithmetic

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Master | Next Rank: 500 Posts
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by phoenix9801 » Sun Jun 27, 2010 12:43 am
Hi, can someone please help to explain the step-by-step instructions (in detail) in the most simplest way and clear to understand.



The ratio, by volume, of soap to alcohol to water in a certain solution is 2:50:100. The solution will be altered so that the ratio of soap to alcohol is doubled while that ratio of soap to water is halved. If the altered solution will contain 100 cubic centimeters of alcohol, how many cubic centimeters of water will it contain?
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by albatross86 » Sun Jun 27, 2010 1:01 am
S:A:W = 2:50:100

We can split this into: S: A = 2:50 and S:W = 2:100

New S:A is doubles => it is now 4:50

New S:W is halved => it is now 1:100

We need the S part to have a common number to "Regroup" the ratio

So let us express S:W as 4:400

So our new regrouped ratio is S:A:W = 4:50:400

From this we can see the ratio of A:W = 50:400 = 1:8

So if alcohol = 100 cubic centimeters, water must be 800 cubic centimeters.
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