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Arithmetic

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Arithmetic

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Wonka Bars sell for $1 each. Willy Wonka also accepts three Wonka Bar wrappers in exchange for a Wonka Bar. Violet has $8 and Veruca has $7. If they decide to pool their money together, buy the maximum possible number of Wonka bars and split the bars equally between them, how many Wonka bars will Veruca have?

A) 10
B) 11
C) 15
D) 20
E) 22

OA is B
I want an Expert to do a breakdown of this question. A contribution will be highly appreciated.

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GMAT/MBA Expert

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Quote:
Wonka Bars sell for $1 each. Willy Wonka also accepts three Wonka Bar wrappers in exchange for a Wonka Bar. Violet has $8 and Veruca has $7. If they decide to pool their money together, buy the maximum possible number of Wonka bars and split the bars equally between them, how many Wonka bars will Veruca have?

A) 10
B) 11
C) 15
D) 20
E) 22

OA is B
I want an Expert to do a breakdown of this question. A contribution will be highly appreciated.
Hi Roland2rule,
Let's take a look at your question.

Voilet and Veruca have a combined total of $15.
Each Wonka bar cost $1.
Therefore, they can get 15 wonka bars.

Now, 15 Wonka bars will generate 15 wrappers.
3 wrappers can be exchanged with 1 Wonka bar.
Therefore, using 15 wrappers they can get 5 wonka bars.

Now these 5 Wonka bars will generate another 5 wrappers.
Using 3 of the wrappers they will get 1 wonka bar.

2 wrappers already left + 1 more wrapper of the last Wonkabar will make 3 wrappers again to get 1 more wonka bar.

Hence,
total Wonkabars they got = 15 + 5 + 1 + 1 = 22

Voilet and Veruca are splitting the bars equally between them, so Veruca will get 11 bars.

Therefore, Option B is correct.

Hope it helps.
I am available if you'd like any follow up.

_________________
GMAT Prep From The Economist
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