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Arithmetic Problem

Expert replies
by vongdn » Wed Oct 06, 2010 8:09 pm
If it took Carlos 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 miles? (note: 1 mile = 5280 feet)

(1) The average speed cycled was greater than 16 ft/sec
(2) The average speed cycled was less than 18 ft/sec


ANSWER --> (1) and (2) together are not sufficient.


The trick here is seeing if the greater than and less part of the answer suffices to figure out of he cycled more than 6 miles. But I figured this out by doing the whole equations out, ie converting ft/sec to ft/min, then multiplying by 30 mins, then converting ft into miles. I did this for both statements, but is there a quicker way?
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Source: — Problem Solving |

by saurabhmahajan » Thu Oct 07, 2010 3:09 am
what i did was that i converted 1/2 hour into sec i.e 1800 sec

stmt 1) more that 16ft/sec = 16*1800 / 5280
same way for stmt 2.
Thanks and regards,
Saurabh Mahajan

I can understand you not winning,but i will not forgive you for not trying.
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by deepak123gmat » Thu Oct 07, 2010 6:54 am
According to me answer is C. both together are sufficient. if we consider 17 ft/sec.
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by deepak123gmat » Thu Oct 07, 2010 6:58 am
please dont bother. silly assumption.
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by diebeatsthegmat » Thu Oct 07, 2010 6:08 pm
vongdn wrote:If it took Carlos 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 miles? (note: 1 mile = 5280 feet)

(1) The average speed cycled was greater than 16 ft/sec
(2) The average speed cycled was less than 18 ft/sec


ANSWER --> (1) and (2) together are not sufficient.


The trick here is seeing if the greater than and less part of the answer suffices to figure out of he cycled more than 6 miles. But I figured this out by doing the whole equations out, ie converting ft/sec to ft/min, then multiplying by 30 mins, then converting ft into miles. I did this for both statements, but is there a quicker way?
speed is between 16 and 18 so speed can be 16,5 or 17,9
when you multiply 1/2 hour or 1800 second * 16,5 the distance is smaller than 6 miles but when 17,9 or 17,5* 1800 the distance is bigger than 6 miles so its insufficient
E
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