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by vishal chugh » Sat Nov 19, 2011 12:07 am
Q. Rectangular Floors X and Y have equal area. If floor X is 12 feet by 18 feet and Floor Y is 9 feet wide, What is the length of Floor Y, in feet?


A. 13.5 B. 18 C. 18.75 D. 21 E. 24
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by shankar.ashwin » Sat Nov 19, 2011 12:16 am
ARea of X = 12*18 = 216
Area of Y = 9* X

GIven, 216 = 9 * Y

Y = 24. E IMO
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by Anurag@Gurome » Sun Nov 20, 2011 11:36 pm
vishal chugh wrote:Q. Rectangular Floors X and Y have equal area. If floor X is 12 feet by 18 feet and Floor Y is 9 feet wide, What is the length of Floor Y, in feet?


A. 13.5 B. 18 C. 18.75 D. 21 E. 24

Solution:
It can be easily observed that one dimension of floor X = 18 feet is twice the given dimension of floor Y = 9 feet.
Hence, since the area has to remain the same for both floors, the other dimension of floor Y should be twice the other dimension of floor X = 12, which makes it 2*12 = 24.
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by Scott@TargetTestPrep » Tue May 12, 2015 4:15 am
vishal chugh wrote:Q. Rectangular Floors X and Y have equal area. If floor X is 12 feet by 18 feet and Floor Y is 9 feet wide, What is the length of Floor Y, in feet?


A. 13.5 B. 18 C. 18.75 D. 21 E. 24
The area of a rectangle is: Area = length x width

We are given that floor X is 12 feet by 18 feet and that floor Y is 9 feet wide. So we can say:

length of X = 12

width of X = 18

width of Y = 9

length of Y = n

We also can say:

Area of Floor X = Area of Floor Y

(length of X)(width of X) = (length of Y)(width of Y)

(12)(18) = 9n

(12)(2) = n

24 = n

The answer is E

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