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mehravikas
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For P.
(b*h)/2
b=4
h=1
Area of P=4/2=2
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Area of shaded regions
Source: Beat The GMAT — Problem Solving |
for P 1/2 *bh = 1/2 * 4 * 1 = 2
for Q L * B = 2 * 1 = 2
for R side of the square is the hypotenuse of a triangle which has side 1 and 1 so the side is sqrt(2) so sqrt(2) * sqrt(2) = 2
for S area is 1.5 so not the choice.
hope this helps.
for Q L * B = 2 * 1 = 2
for R side of the square is the hypotenuse of a triangle which has side 1 and 1 so the side is sqrt(2) so sqrt(2) * sqrt(2) = 2
for S area is 1.5 so not the choice.
hope this helps.
