Area of circle which has a triangle in ita

vishal.pathak wrote:An equilateral triangle that has an area of 93 is inscribed in a circle. What is the area of the circle?
A. π6 B. π9 C. π12 D. 9π √3 E. 18π √3

Any quick way of doing this? OA not available

Kindly recheck the value of area. For one of the options to be correct, the area can't be 93.

An equilateral triangle that has an area of 93 is inscribed in a circle. What is the area of the circle?
A. π6 B. π9 C. π12 D. 9π √3 E. 18π √3

Any quick way of doing this? OA not available

yep, kanwar86 is right..
please check your question again

rijul007 wrote:

An equilateral triangle that has an area of 93 is inscribed in a circle. What is the area of the circle?
A. π6 B. π9 C. π12 D. 9π √3 E. 18π √3

Any quick way of doing this? OA not available

yep, kanwar86 is right..
please check your question again

This is what the question says, this was given to me by a friend so yes, source is not a standard one

vishal.pathak wrote:

rijul007 wrote:

An equilateral triangle that has an area of 93 is inscribed in a circle. What is the area of the circle?
A. π6 B. π9 C. π12 D. 9π √3 E. 18π √3

Any quick way of doing this? OA not available

yep, kanwar86 is right..
please check your question again

This is what the question says, this was given to me by a friend so yes, source is not a standard one

The answer to this question, considering area of equilateral triangle to be 93, is 124π/√3
Approach:
1) Find altitude of equilateral triangle.
2) Centroid divides the altitude (median) of equilateral triangle in the ratio 2:1 with the larger part towards the vertex.
3) Larger part, found in step 2, is the circumradius from which area of circumcircle can be calculated.

rijul007 wrote:

Incorrect: cos 30 = sqrt(3)/2

sqrt(3)/2 = a/2r

or r = a/sqrt(3)