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Area of circle in terms of r?

Expert replies
by Ahmed MS » Thu Jun 16, 2011 10:29 pm
A thin piece of 40 m wire is cut in two. One piece is a circle with radius of r. Other is a square. No wire is left over. Which represents total area of circle and square in terms of r?

a. Πr2
b. Πr2 + 10
c. Πr2 + ¼ π2r2
d. Πr2 + (40 - 2πr)2
e. Πr2 + (10 - ½ Πr)2

The answer is E. Can anyone explain how?

Cheers!
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Source: — Problem Solving |

by Anurag@Gurome » Thu Jun 16, 2011 11:26 pm
Ahmed MS wrote:A thin piece of 40 m wire is cut in two. One piece is a circle with radius of r. Other is a square. No wire is left over. Which represents total area of circle and square in terms of r?

a. Πr2
b. Πr2 + 10
c. Πr2 + ¼ π2r2
d. Πr2 + (40 - 2πr)2
e. Πr2 + (10 - ½ Πr)2
Perimeter of the circle = 2πr
Therefore, perimeter of the square = (40 - 2πr)

Hence, length of each side of the square = (40 - 2πr)/4 = (10 - πr/2)

Therefore, total area of circle and square = (Area of the circle) + (Area of the square) = πr² + (10 - πr/2)²

The correct answer is E.
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by GMATGuruNY » Fri Jun 17, 2011 2:09 am
Ahmed MS wrote:A thin piece of 40 m wire is cut in two. One piece is a circle with radius of r. Other is a square. No wire is left over. Which represents total area of circle and square in terms of r?

a. Πr2
b. Πr2 + 10
c. Πr2 + ¼ π2r2
d. Πr2 + (40 - 2πr)2
e. Πr2 + (10 - ½ Πr)2

The answer is E. Can anyone explain how?

Cheers!
Each answer choice includes πr², the area of the circle.
Eliminate A, which clearly does not include the area of the square.
Since πr² is included in each answer choice, we can ignore the first part of each remaining answer choice.
Our only concern is the second part: the area of the square.

Plug in r = 4.
Circumference of circle = 2πr = 2π*4 ≈ 24.
Perimeter of square = remaining wire = 40-24 = 16.
Side of square = 16/4 = 4.
Area of square = 4² = 16.

Now we plug r=4 into the second part of each answer choice to see which yields our target of 16.

Only answer choice E works:
(10 - ½ Πr)²
= (10 - ½ *3*4)²
= 4²
= 16.

The correct answer is E.
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by Ahmed MS » Fri Jun 17, 2011 6:07 am
Thanks Anurag and GMATGuruNY.

Cheers!
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