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by kanha81 » Mon Apr 20, 2009 8:10 am
Show your work to receive the credit! :)
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by bluementor » Mon Apr 20, 2009 8:20 am
(10^8 - 10^2)/(10^7 - 10^3)

= (10^2)*(10^6 - 1)/(10^3)(10^4 - 1)

I will now approximate the following:

(10^6 - 1) ≈ 10^6
(10^4 - 1) ≈ 10^4

So,

(10^2)(10^6)/(10^3)(10^4)
=10^(2+6-3-4)
=10^1
=10

Choose B.

-BM-
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