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anyone know how to solve this problem?

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by ST » Sun Mar 08, 2009 6:14 pm
anyone knows how to solve this problem?
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by logitech » Sun Mar 08, 2009 7:03 pm
You can convert that equation into:

5^m 2^36 = 2 (2x5)^35

5^m 2^36 = 2 2^35 5^35

so: 5^m = 5 ^35 ; therefore m=35
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by vittalgmat » Sun Mar 08, 2009 9:12 pm
Just got back to the GMAT fray after a 2 month break.

Thought of adding some explanation to Logitech's solution.
Hope he doesnt mind :-)

Every term in this equation is in the denominator. So taking the reciprocal will not alter it in anyway.
here are the steps:

1/5^m . 1/2^36 = 1/(2^36 * (5*2)^35)

Taking reciprocal on both sides:
5^m * 2^36 = 2^36 *5^35
cancelling 2^36,

5^m = 5^35.

Bases are same, so powers can be equated.

m =35

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by logitech » Sun Mar 08, 2009 10:03 pm
vittalgmat wrote:Just got back to the GMAT fray after a 2 month break.
Welcome back Vittal!
LGTCH
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Thank you

by ST » Mon Mar 09, 2009 5:48 am
Thank you so much
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