Another Problem with factors and multiples

Hmm,

3 or 4 = divisible 3+divisible 4 - divisible with 12 ( think like a set )

200/3 = 66 numbers

200/4 = 50 numbers

200/12 = 16 numbers

60+56 - 16 = 100

Am I right ?

3*1(3) to 3*66(198)

So total of 66-1+1 = 66 multiples of 3 (1)

4*1(4) to 4*50(200)

50-1+1 = 50 multiples of 4 (2)

We would have double counted the common multiples of 3 and 4 i.e multiples of 12 which we need to subtract after adding (1) and (2)

12*1 to 12*16

So 16-1+1 = 16 multiples of 12

66+50-16 = 100

Choose C)