BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Another inequality

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Legendary Member
Posts: 1161
Joined: Mon May 12, 2008 2:52 amFollowed by: 1 member
Location: Sydney
Thanked: 23 times

by mehravikas » Sun Oct 04, 2009 3:14 pm
IMO - A

Given that x is -ve
1. x^2 > 9 - therefore x will be less than -3
2. x^3 < -9 - therefore x < -2.3 (guessed on this value because cube root of 8 is 2 so cube root of 9 must be greater than 2).

x < -2.3 but its not sure that x will be less than -3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 869
Joined: Wed Aug 26, 2009 3:49 pmFollowed by: 3 members
Location: California
Thanked: 13 times

by heshamelaziry » Sun Oct 04, 2009 4:06 pm
mehravikas wrote:IMO - A

Given that x is -ve
1. x^2 > 9 - therefore x will be less than -3
2. x^3 < -9 - therefore x < -2.3 (guessed on this value because cube root of 8 is 2 so cube root of 9 must be greater than 2).

x < -2.3 but its not sure that x will be less than -3
I don't understand why 2 is insufficient, x < -3 or x > 3, and since x is -ve, it should be sufficient ???
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1161
Joined: Mon May 12, 2008 2:52 amFollowed by: 1 member
Location: Sydney
Thanked: 23 times

by mehravikas » Sun Oct 04, 2009 4:14 pm
How can you say that x < -3 in statement 2. What will be the cube root of 9 it will certainly be > 2

but the statement says x^3 < -9, therefore x < -2.3 (this is not an exact cube root)

If x < -2.3 then x could be the following:

1. x < -2.5
2. x < -2.9
3. x < -3

We cannot deduce the value of x.
heshamelaziry wrote:
mehravikas wrote:IMO - A

Given that x is -ve
1. x^2 > 9 - therefore x will be less than -3
2. x^3 < -9 - therefore x < -2.3 (guessed on this value because cube root of 8 is 2 so cube root of 9 must be greater than 2).

x < -2.3 but its not sure that x will be less than -3
I don't understand why 2 is insufficient, x < -3 or x > 3, and since x is -ve, it should be sufficient ???
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1