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I don't understand why 2 is insufficient, x < -3 or x > 3, and since x is -ve, it should be sufficient ???mehravikas wrote:IMO - A
Given that x is -ve
1. x^2 > 9 - therefore x will be less than -3
2. x^3 < -9 - therefore x < -2.3 (guessed on this value because cube root of 8 is 2 so cube root of 9 must be greater than 2).
x < -2.3 but its not sure that x will be less than -3
heshamelaziry wrote:I don't understand why 2 is insufficient, x < -3 or x > 3, and since x is -ve, it should be sufficient ???mehravikas wrote:IMO - A
Given that x is -ve
1. x^2 > 9 - therefore x will be less than -3
2. x^3 < -9 - therefore x < -2.3 (guessed on this value because cube root of 8 is 2 so cube root of 9 must be greater than 2).
x < -2.3 but its not sure that x will be less than -3
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