Still trying to work this one...

The part I can't seem to figure out is how to find the sum consecutive even integers. I know the sum of consecutive integers is the average times the number of terms but the even part is messing me up. Here is where I am...

The average should be 100+2 / 2 = 51

The number of terms from A to B is B - A + 1 so B - A is 100-2 = 98, then divide by 2 since I'm only concerned with even numbers and add 1 which gives me 50 (49 + 1).

So now the sum would be 50 * 51 = 2550. But the function said F(100) + 1 so that equals 2551.

Now I think the question is asking for the smallest prime factor of 2551 and nothing seems to go into it so to me it seems like a prime number which makes the answer E.

Am I close??

The only way to solve this question is first find out the sum of the all the consecutive even integers by using the arithmetic progression formula

Sum = 2551 as rightly pointed out...You have to divide 2551 by all the prime numbers less than 40 (3,5,7,9,11,13,17,19,23,29,31,37)....

Another way to find out if a number x is prime or not....find out sqr. rt x....if x is not divisible by any number between 1 and sqr rt. x...then x is prime (although even this is a little time consuming!!)

.. allen r u sure u have the q right ... not that i have a poblem with this q but i remeber to have answered a identical q .. but in that the fun h(n) was equal the multiplication of all numbers from 2 to n .. and the answer to that one was also E (that is greater than 40) ... moreover i dont think gmat wuld just giv u a number and ask to find the smallest prime number ...