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Anna wants to distribute chocolates among her four children in the ratio \(\dfrac12:\dfrac15:\dfrac16:\dfrac1{12}.\) How

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by Gmat_mission » Thu Oct 08, 2020 3:45 am
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Anna wants to distribute chocolates among her four children in the ratio \(\dfrac12:\dfrac15:\dfrac16:\dfrac1{12}.\) How many minimum chocolates should she buy, so that she can distribute the chocolates in the given ratio?

a. 30
b. 45
c. 57
d. 90
e. 120

Answer: C

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Re: Anna wants to distribute chocolates among her four children in the ratio \(\dfrac12:\dfrac15:\dfrac16:\dfrac1{12}.\)

by Scott@TargetTestPrep » Fri Oct 16, 2020 5:52 am
Gmat_mission wrote: ↑
Thu Oct 08, 2020 3:45 am
 Anna wants to distribute chocolates among her four children in the ratio \(\dfrac12:\dfrac15:\dfrac16:\dfrac1{12}.\) How many minimum chocolates should she buy, so that she can distribute the chocolates in the given ratio?

a. 30
b. 45
c. 57
d. 90
e. 120

Answer: C

Solution:

Since the LCM of 2, 5, 6, and 12 is 5 x 12 = 60; we can multiply each fraction by 60 so that each fraction becomes a whole number: 1/2 x 60 = 30, 1/5 x 60 = 12, 1/6 x 60 = 10 and 1/12 x 60 = 5. Therefore, the ratio can be written as 30 : 12 : 10 : 5 and, hence, the minimum number of chocolates she should buy is 30 + 12 + 10 + 5 = 57.

Answer: C

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