Ann has a deck of 52 cards, made up of four suits, each with

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BTGmoderatorLU: Moderator; Posts: 2650; Joined: Sun Oct 15, 2017 1:50 pmFollowed by: 6 members

by BTGmoderatorLU » Sat Aug 17, 2019 7:22 am

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Source: Princeton Review

Ann has a deck of 52 cards, made up of four suits, each with cards numbered 1 through 13. If she selects a card at random, what is the probability that she selects a 2 or 7 or 9?

A. 1/3825
B. 1/64
C. 3/52
D. 3/13
E. 3/4

The OA is D

Source: Beat The GMAT — Problem Solving | Sat Aug 17, 2019 7:22 am

swerve: Legendary Member; Posts: 2604; Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

by swerve » Sat Aug 17, 2019 2:45 pm

Total number if desired cards is $3\cdot 4 = 12$ (3 numbers and 4 suits each)

Total cards = 52.

Probability $= \frac{12}{52} = \frac{3}{13} \Rightarrow$ option __D__

deloitte247: Legendary Member; Posts: 2214; Joined: Fri Mar 02, 2018 2:22 pmFollowed by: 5 members

by deloitte247 » Sun Aug 18, 2019 7:11 am

Total cards = 52 cards made up of 4 suits
Total number of 2's = 4
Total number of 7's = 4
Total number of 9's = 4
Total favourable outcome = 4 + 4 + 4 = 12
Total possible outcome = Total cards = 52
Probability of selecting a 2, 7 or 9 = $$\frac{12}{52}=\frac{3}{13}$$
Answer = option D

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