Andrew has a certain number of coins in his pocket. He has

BTGmoderatorDC wrote:Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.25. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?

A. 9
B. 10
C. 18
D. 20
E. 21

OA E

Source: EMPOWERgmat

Say Dime is represented by d, Nickles by n and Quarter by q

Thus, d = 3q; n = 6d. Thus, n = 3*6d = 18d

Given, Andrew has a total of $10.15, we have

0.05n + 0.10d + 0.25q = 10.15

5n + 10d + 25q = 1015

n + 2d + 5q = 203

18q + 2*3q + 5q = 203; replacing the value of n and d

18q + 6q + 5q = 203

29q = 203

q = 7

=> d = 3q = 3*7 = 21

The correct answer: E

Hope this helps!

-Jay
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BTGmoderatorDC wrote:Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.25. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?

A. 9
B. 10
C. 18
D. 20
E. 21

OA E

Source: EMPOWERgmat

Let x = number of QUARTERS in pocket
So, 0.25x = VALUE of quarters in pocket

He has three times as many dimes as quarters
So, 3x = number of DIMES in pocket
So, 0.10(3x) = 0.3x = VALUE of dimes in pocket

He has six times as many nickels as dimes.
So, (6)(3x) = number of NICKELS in pocket
In other words, 18x = number of NICKELS in pocket
So, 0.05(18x) = 0.9x = VALUE of nickels in pocket

He has a total of $10.15
So: 0.25x + 0.3x +0.9x = $10.15
Simplify: 1.45x = $10.15
Solve: x = 10.15/1.45 = 7

So there are 7 QUARTERS, 21 DIMES and 126 NICKELS

Answer: E

Cheers,
Brent

BTGmoderatorDC wrote:Andrew has a certain number of coins in his pocket. He has three times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.25. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?

A. 9
B. 10
C. 18
D. 20
E. 21

We can let q = number of quarters; thus, there are 3q dimes and 6(3q) = 18q nickels. We can create the equation for the value of the coins:

0.05(18q) + 0.10(3q) + 0.25q = 10.15

Multiplying the equation by 100, we have:

5(18q) + 10(3q) + 25q = 1015

90q + 30q + 25q = 1015

145q = 1015

q = 7

Since there are three times as many dimes as quarters, there are 3(7) = 21 dimes.

Answer: E