The rising in the level of water in the cylinder is due to the increase in volume that is equal to the volume of the spherical ball.

Then the volume increased (the increase volume is in the shape of a cylinder):
V(I) = r^2*Pi*Height = 14^2*Pi*4 = 784*Pi

The volume of the sperical ball (which cause the increase in volume of the original cylinder):
V(S) = 4/3*Pi*r^3

V(I) = V(S), then:
4/3*Pi*r^3 = 784*Pi
r^3 = 784* 3/4 = 588
Then r = cuberoot (588)

Pick A.

diebeatsthegmat wrote:A spherical ball, when immersed in a cylinder of base radius 14cm, raises the level of water in the cylinder by 4cm. Find the radius of the ball in cm
A) cuberoot 588
B) cuberoot 147/2
C) Sqrt 94/7
D) cuberoot 147
E) Cannot be determined
how to sold this guys?
i know this problem was posted in this forum before but i am not comfortable with the solution....

There is one simple physics attribute in this problem
i.e the amount of fluid displaced is equal to the volume of the object...

Now...

when a sphere is added in a tank, the height changes by 4

so lets consider the original volume of the liquid in the cylinder to be = V = pi * R^2 * h

where R= 14 given and h is the height of fluid before we immersed the object

Let V` = volume of water in the cylinder after the object is immersed = pi * R^2 * (h+4)

so now the volume of the sphere = V`- V = pi * R^2 * 4


Also volume of a sphere = 4/3 * pi * r^3, where r is the radius of the sphere...

Therefore
4/3 * pi * r^3 = pi * R^2 * (h+4)

=> r = cuberoot of (588)

IMO A

Hope this helps...

limestone wrote:The rising in the level of water in the cylinder is due to the increase in volume that is equal to the volume of the spherical ball.

Then the volume increased (the increase volume is in the shape of a cylinder):
V(I) = r^2*Pi*Height = 14^2*Pi*4 = 784*Pi

The volume of the sperical ball (which cause the increase in volume of the original cylinder):
V(S) = 4/3*Pi*r^3

V(I) = V(S), then:
4/3*Pi*r^3 = 784*Pi
r^3 = 784* 3/4 = 588
Then r = cuberoot (588)

Pick A.

why do we know this ? " The rising in the level of water in the cylinder is due to the increase in volume that is equal to the volume of the spherical ball. "

Hi,

This is a little out side the scope. It's about physic.

When you submerge something into the water, that thing will take the room of some water. As water cannot be compressed, then that room must be equal to the volume of the object you have just submerged ( of course, that object must not interact with or absorb water).

This method is used to calculate the volume of complex objects. For instance,people submerge a ring into a cup of water that has a parimeter on its side, then see how much the column of water has risen. Using the parimeter printed on the cup, people can figure out the volume of risen water (as in the above case, I use base's area * increased height to find the increased volume). And that risen volume is also the volume of the ring.

diebeatsthegmat wrote: why do we know this ? " The rising in the level of water in the cylinder is due to the increase in volume that is equal to the volume of the spherical ball. "

It is the Archimede's principle. More to do with physics. This has a funny history. Archimedes+EUREKA. read this snippet from wikipedia:

"This exclamation is most famously attributed to the ancient Greek scholar Archimedes; he reportedly proclaimed "Eureka!" when he stepped into a bath and noticed that the water level rose - he suddenly understood that the volume of water displaced must be equal to the volume of the part of his body he had submerged. This meant that the volume of irregular objects could be calculated with precision, a previously intractable problem. He is said to have been so eager to share his realisation that he leapt out of his bathtub and ran through the streets of Syracuse naked."


(In case, you are not comfortable with this problem, I suggest you to Ignore this question.)

limestone wrote:Hi,

This is a little out side the scope. It's about physic.

When you submerge something into the water, that thing will take the room of some water. As water cannot be compressed, then that room must be equal to the volume of the object you have just submerged ( of course, that object must not interact with or absorb water).

This method is used to calculate the volume of complex objects. For instance,people submerge a ring into a cup of water that has a parimeter on its side, then see how much the column of water has risen. Using the parimeter printed on the cup, people can figure out the volume of risen water (as in the above case, I use base's area * increased height to find the increased volume). And that risen volume is also the volume of the ring.

physic??? i am hella bad at physic... always get D lol

kvcpk wrote:

diebeatsthegmat wrote: why do we know this ? " The rising in the level of water in the cylinder is due to the increase in volume that is equal to the volume of the spherical ball. "

It is the Archimede's principle. More to do with physics. This has a funny history. Archimedes+EUREKA. read this snippet from wikipedia:

"This exclamation is most famously attributed to the ancient Greek scholar Archimedes; he reportedly proclaimed "Eureka!" when he stepped into a bath and noticed that the water level rose - he suddenly understood that the volume of water displaced must be equal to the volume of the part of his body he had submerged. This meant that the volume of irregular objects could be calculated with precision, a previously intractable problem. He is said to have been so eager to share his realisation that he leapt out of his bathtub and ran through the streets of Syracuse naked."


(In case, you are not comfortable with this problem, I suggest you to Ignore this question.)

i know the story of loving to be nude after finding a principle of Archimedes....
i dont understand much about physic but i will consider this a kind of rule in solving this sort of problem,,, i dont think they will test us physic in math section.
thank you both limestone and kvcpk