- The dealership sells only sedans and coupes
- The dealership sell only in two colors; red & blue
- The dealership sold 9000 vehicles last year, half of each were red
So, last year, 4500 red vehicles and 4500 blue vehicles were sold


Target question => How many coupes (both red & blue) did the dealership sell last year?


Statement 1 => The dealership sold three times as many coupes as red sedans last year
If red sedans sold = x then blue coupes sold = 3x but red coupes and blue sedans sold are unknown so statement 1 is NOT SUFFICIENT


Statement 2 => The dealership sold half as many blue sedans as blue coupes last year
If blue sedans sold = y, then blue coupes = 2y
Since all blues = 4500 then y + 2y = 4500; y = 1500 and 2y = 3000
We don't know the value of red coupes and sedans sold so statement 2 is NOT SUFFICIENT


Combining both statements together =>
In statement 1 => Blue coupes = 3x
In statement 2 => It is 3000
So blue coupes = 3000 and red sedans = 1000 hence red coupes = 4500 - 1000 = 3500
Total coupes = 3500 + 3000 = 6500
Both statements together ARE SUFFICIENT


Answer = C