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by umaa » Thu Jul 17, 2008 1:36 am
In an amusement park there’s a fishing mini-game. There are fish numbered 201 to 450. If I fish out one fish randomly, what’s the probability that the ticket selected at random will have a hundreds digit of 4, which will win me a cool prize?


a. 50/250
b. 49/250
c. 1/4
d. 1/5
e. 2/5

Answer: d
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by sudhir3127 » Thu Jul 17, 2008 2:00 am
whats the difference between option A and D

i am getting it as 51/250
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by umaa » Thu Jul 17, 2008 2:16 am
right. the first one might be, 51/250. I'm getting 61/250.


First and Last possible numbers:

(444-204)/4 = 240/4 = 60 + 1 = 61

Probability would be, 61/250.

Please let me know what i'm doing wrong
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by parallel_chase » Thu Jul 17, 2008 2:21 am
sudhir3127 wrote:whats the difference between option A and D

i am getting it as 51/250
i am also getting 51/250
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by parallel_chase » Thu Jul 17, 2008 2:24 am
umaa wrote:right. the first one might be, 51/250. I'm getting 61/250.


First and Last possible numbers:

(444-204)/4 = 240/4 = 60 + 1 = 61

Probability would be, 61/250.

Please let me know what i'm doing wrong

First number is 400 last number is 450
450-400= 50 +1 = 51

450-201= 249 +1=250

51/250
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