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all three of these devices

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by sanju09 » Sat Aug 14, 2010 2:08 am
In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x - y is:

A. 65

B. 55

C. 45

D. 35

E. 25

[spoiler]Source: gmatclub.com[/spoiler]
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by nithi_mystics » Sat Aug 14, 2010 5:14 am
Greatest possible number of households that have all three of these devices = 55 (since that's the smallest of the numbers 80,75 and 55)
Lowest possible number of households that have all three of these devices = 10

So, x-y = 45.

Pls check the thread mentioned below to find the lowest possible number -
https://www.beatthegmat.com/least-value- ... tml#195798

sanju09 wrote:In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x - y is:

A. 65

B. 55

C. 45

D. 35

E. 25

[spoiler]Source: gmatclub.com[/spoiler]
Thanks
Nithi
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