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by candela.tartiere » Tue Feb 26, 2013 3:08 am
if k and m are numbers such that k + m = 20 and k^2 + m^2 = 289, then the value of the product km is?
A. between 20 and 60
B. between 60 and 100
C. between 100 and 150
D. between 150 and 200
E. greater than 200
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by Anurag@Gurome » Tue Feb 26, 2013 3:14 am
candela.tartiere wrote:if k and m are numbers such that k + m = 20 and k^2 + m^2 = 289, then the value of the product km is?
(k + m)² = k² + m² + 2km

Hence, km = [(k + m)² - (k² + m²)]/2 = [20² - 289]/2 = [400 - 289]/2 = 111/2 = 55.5

The correct answer is A.
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