the LCM of polynomials (36x^2-49) and (6x^2-25x+21)is a (x-3) b (x-3)^2 (6x-7) c (x-3) (6x-7) (6x+7) d none of these

romitvsingh wrote:the LCM of polynomials (36x^2-49) and (6x^2-25x+21)is a (x-3) b (x-3)^2 (6x-7) c (x-3) (6x-7) (6x+7) d none of these (36x^2-49) = (6x-7)*(6x+7), and (6x^2-25x+21)= (6x-7)*(x-3) LCM=(X-3)*(6X+7)*(6X-7) HENCE C

Well bro killer1387 you have committed a minor mistake... The answer should be D and not C. the reason is that see the factors once...\ the factors of 6x^2 - 9x - 14x + 21 = 3x (2x - 3) - 7 (2x - 3) = (3x - 7) (2x - 3) hence the factors are (3x - 7) (2x - 3) (6x - 7) (6x + 7) none of the options A , B or C are the above hence D. I am sure of this... please see this and let me know By the way what is the OA romitvsingh...

amit.trivedi@ymail.com wrote:Well bro killer1387 you have committed a minor mistake... The answer should be D and not C. the reason is that see the factors once...\ the factors of 6x^2 - 9x - 14x + 21 = 3x (2x - 3) - 7 (2x - 3) = (3x - 7) (2x - 3) hence the factors are (3x - 7) (2x - 3) (6x - 7) (6x + 7) none of the options A , B or C are the above hence D. I am sure of this... please see this and let me know By the way what is the OA romitvsingh... Nope, you made a mistake: 9 + 14 = 23; not 25 The answer is C.

romitvsingh wrote:the LCM of polynomials (36x^2-49) and (6x^2-25x+21)is a (x-3) b (x-3)^2 (6x-7) c (x-3) (6x-7) (6x+7) d none of these (36x^2 - 49) = (6x + 7)(6x - 7) (6x^2 - 25x + 21) = 6x^2 - 18x - 7x + 21 = 6x(x - 3) - 7(x - 3) = (x - 3)(6x - 7) Therefore, LCM of (36x^2 - 49) and (6x^2 - 25x + 21) = [spoiler](x - 3)(6x + 7)(6x - 7) [/spoiler] The correct answer is C.