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by GmatKiss » Fri May 18, 2012 11:07 am
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

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by GMATGuruNY » Fri May 18, 2012 11:55 am
GmatKiss wrote:Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

· 51
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· 53
· 54
· 55
Always look at the answer choices.
52/4 = 13.
Thus, the average age must be around 13.

Let J=13.
Then, according to the conditions given, K=15, L=12, and M=14.
Sum = 13+15+12+14 = 54.

The correct answer is D.
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by heymayank08 » Sat May 19, 2012 11:18 pm
mitch i didnt understand the
52/4 step of yours...
cn u pls explain...
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by darontan » Sat May 19, 2012 11:52 pm
from the question, we know that the age is integer

J=K-2
K=L+3
M=J+1

Sum = J+K+L+M = (K-2) + K + (K-3) + ((K-2)+1) = 4K-6

From the answer choices, K is integer only when Sum is 54 (D)
4K-6=54, K=15
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by Anurag@Gurome » Sun May 20, 2012 8:20 am
GmatKiss wrote:Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?

· 51
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Say, age of Kylie is n years.
Age of Joan is (n - 2) years
Age of Lilian is (n - 3) years
Age of Miriam is (n - 1) years

Hence, total age = (4n - 6) years

Hence, the total age must be 6 less than an integer multiple of 4, that is 2 less than an integer multiple of 4. Only such option is 54.

Hence, the correct answer is D.
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by GMATGuruNY » Sun May 20, 2012 8:46 am
heymayank08 wrote:mitch i didnt understand the
52/4 step of yours...
cn u pls explain...
The answers choices -- which represent the sum of the 4 ages -- are all around 52.
The problem describes 4 ages that seem relatively close to each other.
Thus, the average age must be close to 52/4 = 13.
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