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Absolute Value!!!!

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by hamxa » Thu Mar 11, 2010 8:50 am
Ian please explain in light of corrected statement B:

if y .= 0, what is the value of x ?

1. |x-3| >= y
2. |x-3| <= -y

please explain how it wraps to B only.
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by Thouraya » Tue May 31, 2011 7:29 am
@Ian or @Kevin, can you please explain in detail as I have been confused with the conversation above. This is the official question and the OA for this is B (Gmatprep):

If y>=0, what is the value of x?
1) absolute value x-3>=y
2)absoulte value x-3<=-y


The way I solve it: 1 is not sufficient as we have two unknowns, so there is no way we can come up with a value for x. Statement 2 is impossible, absolute values are always positive, so this could not possibly be less than or equal to -y. Is this why you say OA is E? Appreciated
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by krnverma » Fri Sep 02, 2011 12:34 am
Hi Thouraya,
You are missing one value of y when you say that the second statement is not possible.
The question it self says y>=0. So, if y = 0 then for |x-3| to be equal to 0, x will have to be 3.

And the question asks us the value for x.

So statement 2 alone is sufficient.

Thanks
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by prateek_guy2004 » Fri Sep 02, 2011 1:55 pm
Well i am not convinced with B either It should be C.

statement 1 says |x-3|>=y
x>=y+3
Insufficient

Statement 2 says lx-3l is greater than or equal to -y

x>=-y+3

Insufficient

After concluding both statements +y and -y can be eliminated and x>=6

Hence C[spoiler][/spoiler]
Don't look for the incorrect things that you have done rather look for remedies....

https://www.beatthegmat.com/motivation-t90253.html
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by viju9162 » Fri Oct 14, 2011 8:50 am
Can anyone provide a brief explanation to the problem ? It will be very helpful.
"Native of" is used for a individual while "Native to" is used for a large group
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by studentps2011 » Fri Oct 28, 2011 12:50 pm
Statement 1: doesn't give a definite value for x;
y can be any value equal to or greater than zero and correspondingly we can get different values for x.

Statement 2: y is equal to zero or a positive number, as per the question stem. Hence -y should be zero or a negative number.

|x-3| is given as less than or equal to -y
ie., |x-3| is equal to zero or a negative number.

Since modulus of a number or expression can never be negative, |x-3| has to be zero.

Therefore,
x-3=0
x=3
OR
-x+3=0,
again x=3. (Sufficient)
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by gmatdriller » Fri Oct 28, 2011 10:41 pm
In light of the revised question, as posted by "Hamxa", the explanations given by
Studentps2011" holds true.
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