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abs value equation

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by canuckclint » Tue Nov 04, 2008 9:32 pm
If |x| + |y| = -x – y and xy does not equal 0, which of the following must be true?
x + y > 0
x + y < 0
x – y > 0
x – y < 0
x^2 – y^2 > 0
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Re: abs value equation

by logitech » Tue Nov 04, 2008 9:54 pm
canuckclint wrote:If |x| + |y| = -x – y and xy does not equal 0, which of the following must be true?
x + y > 0
x + y < 0
x – y > 0
x – y < 0
x^2 – y^2 > 0
|x| + |y| = -x – y

tells us both X and Y are negatives. We also know that XY is not 0, so X and Y are not 0

X+Y = needs to be negative too.
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by cramya » Tue Nov 04, 2008 10:03 pm
b) is what I get (since its must be true)
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by logitech » Tue Nov 04, 2008 10:04 pm
cramya wrote:b) is what I get (since its must be true)


Now this is called confidence! 8)
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by raunekk » Tue Nov 04, 2008 10:13 pm
one more for B...
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by canuckclint » Tue Nov 04, 2008 10:23 pm
me three for B
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by Fab » Wed Nov 05, 2008 10:17 am
B either.
IXI + IYI = -(X+Y), so: + = -(-)
Then, X+Y<0

Hope it helps.
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by Fab » Wed Nov 05, 2008 10:20 am
B either.
IXI + IYI = -(X+Y), so: + = -(-)
Then, X+Y<0

Hope it helps.
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by Fab » Wed Nov 05, 2008 10:20 am
B either.
IXI + IYI = -(X+Y), so: + = -(-)
Then, X+Y<0

Hope it helps.
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by vivek.kapoor83 » Wed Nov 05, 2008 11:38 am
1 more vote for B>>>>>>>>>>>>>>>>>>>>>..OA pls
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